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Reply With Quote= on it's own isn't a comparison operator. You need ==Originally Posted by david4ie
This is the one that has bitten everyone on the ass at some stage.
php image display problem
Hey
I was wondering if anybody knows how to display an image based on the url of a website. I have one website running on two different domain names and I would like the logo to change bases on the url.
This is what ive got but it doesn't seem to work:
ThanksPHP Code:<?php
$url = $_SERVER['HTTP_HOST']
if ( $url = 'www.example.com')
{
echo "<a href=\"/\"><img src=\"img/logo.gif\" border=0></a>";
}
else if ( $url = 'www.example2.com' )
{
echo "<a href=\"/\"><img src=\"img/logo2.gif\" border=0></a>";
}
?>
= on it's own isn't a comparison operator. You need ==
This is the one that has bitten everyone on the ass at some stage.
First you shouldn't do that for SEO purposes, duplicate content but anyhow there is something I use to do in the past.
saved images (logo) as domain.ie and domain.com then used php to set the path.
PHP Code:<img src='images/".str_replace("www.","",$_SERVER['HTTP_HOST']).".gif' alt='' />
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