php image display problem

david4ie · #1 (**permalink**) 08-05-2007, 09:57 PM

Hey

I was wondering if anybody knows how to display an image based on the url of a website. I have one website running on two different domain names and I would like the logo to change bases on the url.

This is what ive got but it doesn't seem to work:

PHP Code:

  <?php
$url = $_SERVER['HTTP_HOST']
if ( $url = 'www.example.com') 
{
echo   "<a href=\"/\"><img src=\"img/logo.gif\" border=0></a>";
}
else if ( $url = 'www.example2.com' )
{
echo "<a href=\"/\"><img src=\"img/logo2.gif\" border=0></a>";
}
?>

Thanks

niall · #2 (**permalink**) 08-05-2007, 11:03 PM

Quote:

Originally Posted by david4ie

PHP Code:

  <?php
if ( $url = 'www.example.com') 
?>

= on it's own isn't a comparison operator. You need ==

This is the one that has bitten everyone on the ass at some stage.

louie · #3 (**permalink**) 08-05-2007, 11:06 PM

First you shouldn't do that for SEO purposes, duplicate content but anyhow there is something I use to do in the past.
saved images (logo) as domain.ie and domain.com then used php to set the path.

PHP Code:

  <img src='images/".str_replace("www.","",$_SERVER['HTTP_HOST']).".gif' alt='' />

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