file_get_contents not working

Discussion in 'Coding Help' started by amber.long83, Nov 12, 2009.

  1. amber.long83

    amber.long83 New Member

    Hello all,

    This is my code:

    PHP Code:
    $url = "Show.php?ShowID=1";
    $str = file_get_contents($url);
    echo $str;

    That's supposed to get the contents of show.php with showID as 1. But this doesn't work. Just typing show.php works, but the ?showID=1 does not work.

    How could I make it so that it works?

  2. php.allstar

    php.allstar New Member


    You are calling the file in the local filesystem. This method does not support parameters.

    If you use a http wrapper for your function call you will be able to pass parameters

    Be careful with this function and ensure that you don't have allow_url_fopen enabled in your php.ini file, although this is generally disabled on webhosts who know what they are doing.

    Personally, I'd use cURL to include file contents to a variable although you may have to enable cURL on your server for this...


    function includeFile($url) {

    // Initiate the curl session
    $ch = curl_init();
    $timeout = 5;

    // Point curl to the irl we want
    curl_setopt($ch, CURLOPT_URL, $url);

    // Set some cURL options
    curl_setopt($ch, CURLOPT_HEADER, 0);
    curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt ($ch, CURLOPT_CONNECTTIMEOUT, $timeout);

    // Get the file contents
    $file_contents = curl_exec($ch);

    // Close the curl session

    $content = implode('', array($file_contents));

    // Return the content
    return $content;


    $str = includeFile("http://www.domain.tld/Show.php?ShowID=1");


    You could also try something like this to just initialise your variable before your call file_get_contents, then tell show.php to do something if the $showID variable isset...


    $showID = 1;

    $url = "Show.php";
    $str = file_get_contents($url);
    echo $str;

  3. amber.long83

    amber.long83 New Member

    thanks for give me solution

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