PHP preg_replace question

[ziycon]

The below line will remove all alphanumeric characters, what I'm trying to do is remove all alphanumeric characters but replace all spaces with '-'. Will I just need to have two preg_replace statements or can it be done in the one line?

[COLOR=#0000bb]preg_replace[/COLOR][COLOR=#007700]([/COLOR][COLOR=#dd0000]“/[^a-zA-Z0-9\s]/”[/COLOR][COLOR=#007700], [/COLOR][COLOR=#dd0000]“”[/COLOR][COLOR=#007700], [/COLOR][COLOR=#0000bb]$string[/COLOR][COLOR=#007700])[/COLOR]

So this line:

Test data's - "testing"

would become:

Test-datas-testing

 

[php.allstar]

Hi, try this:

<?php

     $string = 'Test data\'s - "testing" ';
     
     $patterns = array();
     $patterns[0] = '/[^a-zA-Z0-9\s]/';
     $patterns[1] = '/\s+/';

     $replacements = array();
     $replacements[0] = '';
     $replacements[1] = '-';
     
     echo preg_replace($patterns, $replacements, trim($string));

?>

there's probably a more eloquent way to get rid of the trailing whitespace with a modifier as opposed to using trim() but I can't think of it at this moment!

Patterns and replacements can be sent as indexed arrays instead of strings as I've demonstrated here.

 

[php.allstar]

ah yes, that trailing whitespace issue was annoying me so I had to find the solution! Try this instead:

<?php

     $string = 'Test data\'s - "testing" ';
     
     $patterns = array();
     $patterns[0] = '/[^a-zA-Z0-9\s]|\s$/';
     $patterns[1] = '/\s+/';

     $replacements = array();
     $replacements[0] = '';
     $replacements[1] = '-';
     
     echo preg_replace($patterns, $replacements, $string);

?>

Added |\s$ to the first pattern to match the trailing whitespace as well as non alphanumeric characters

 

[ziycon]

Nice one, your a star, been bugging me for ages. Thanks again.

 

[php.allstar]

Glad to have helped! Please click the "Thanks" link under my post as seeing it makes me feel all warm and fuzzy!